Seja a expressão: S = ( A + B + C ) . ( A ¯ + B ¯ + C ) {\displaystyle S=(A+B+C).({\bar {A}}+{\bar {B}}+C)}
Simplificação:
Lista de exercício álgebra booleana.
S 1 = ( A + B + C ) . ( A ¯ + B + C ¯ ) {\displaystyle S_{1}=(A+B+C).({\bar {A}}+B+{\bar {C}})}
S 2 = ( A C ¯ + B + D ¯ ) + C ( A C D ¯ ) {\displaystyle S_{2}=({\overline {{\overline {AC}}+B+D}})+C({\overline {ACD}})}
S 3 = ( ( A + B ) . C ¯ ) + ( D ( C + B ) ¯ ) {\displaystyle S_{3}=({\overline {(A+B).C}})+({\overline {D(C+B)}})}
S 4 = ( A ¯ + B ¯ + C ¯ ) . ( A + B + C ¯ ) {\displaystyle S_{4}=({\bar {A}}+{\bar {B}}+{\bar {C}}).(A+B+{\bar {C}})}
S 5 = A ¯ . B ¯ . C + A ¯ . B . C + A ¯ . B . C ¯ + A . B . C + A . B C ¯ {\displaystyle S_{5}={\bar {A}}.{\bar {B}}.C+{\bar {A}}.B.C+{\bar {A}}.B.{\bar {C}}+A.B.C+A.B{\bar {C}}}
S = ( A + B ¯ ) {\displaystyle S=({\overline {A+B}})}
S = A . B {\displaystyle S=A.B\,}
S = A ⊕ B {\displaystyle S=A\oplus B\,}
S = A ¯ {\displaystyle S={\bar {A}}\,}
S = A + B {\displaystyle S=A+B\,}
S = B C D ¯ + B C ¯ D ¯ + B ¯ C D ¯ + B ¯ C ¯ D ¯ {\displaystyle S=BC{\bar {D}}+B{\bar {C}}{\bar {D}}+{\bar {B}}C{\bar {D}}+{\bar {B}}{\bar {C}}{\bar {D}}\,}
S = ( C + D ) . ( C + D ¯ ) {\displaystyle S=(C+D).(C+{\bar {D}})}
S = A B C ¯ D + A ¯ B ¯ C D ¯ + A ¯ B ¯ C ¯ D ¯ + A ¯ B ¯ C ¯ D {\displaystyle S=AB{\bar {C}}D+{\bar {A}}{\bar {B}}C{\bar {D}}+{\bar {A}}{\bar {B}}{\bar {C}}{\bar {D}}+{\bar {A}}{\bar {B}}{\bar {C}}D}
S = ( ( A . B ¯ ) + ( C . D ¯ ) ¯ ) + A ( A + B ¯ ) + B ( C + D ¯ ) {\displaystyle S=({\overline {({\overline {A.B}})+({\overline {C.D}})}})+A({\overline {A+B}})+B({\overline {C+D}})}
S = ( A ( B + C ¯ ) ¯ ) . ( ( A ¯ + C ) + B ¯ ¯ ) {\displaystyle S=({\overline {A({\overline {B+C}})}}).({\overline {({\bar {A}}+C)+{\bar {B}}}})}