CEL018702 2019 1 AULA08

1 Correção AT2

1.1 Questão 1

millman

$I_M=\frac{V_1}{R_1}+\frac{V_2}{R_2}$

$I_M=\frac{50}{10}+\frac{-12}{6}=5+-(2)=3A$

$\frac{1}{R_M}=\frac{1}{R_1}+\frac{1}{R_2}$

$\frac{1}{R_M}=\frac{1}{10}+\frac{1}{6}$

$R_M=3,75\mathrm{\Omega }$

$V_M=I_M.R_M=3.3,75=11,25V$

$V_M+R_M.I+R_3.I+R_4.I=0$

$-11,25+3,75.1+2.I+R_4.1=0$

$R_4=11,25-3,75-2=5,5\mathrm{\Omega }$

1.2 Questão 2

$ 1 0.000005 10.20027730826997 50 5 43
v 80 256 80 112 0 0 40 48 0 0 0.5
r 80 112 192 112 0 12
r 192 112 192 256 0 6
r 192 112 320 112 0 10
r 320 112 320 256 0 4
i 416 256 416 112 0 4
w 320 112 416 112 0
w 416 256 320 256 0
w 192 256 320 256 0
w 80 256 192 256 0

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