IM=V1R1+V2R2
IM=5010+−126=5+−(2)=3A
1RM=1R1+1R2
1RM=110+16
RM=3,75Ω
VM=IM.RM=3.3,75=11,25V
VM+RM.I+R3.I+R4.I=0
−11,25+3,75.1+2.I+R4.1=0