Edição das 13h02min de 17 de fevereiro de 2016

Fatoração

Seja a expressão: $S=(A+B+C).({\bar {A}}+{\bar {B}}+C)$

Simplificação:

$S_{1}=(A+B+C).({\bar {A}}+B+{\bar {C}})$

$S_{2}=({\overline {{\overline {AC}}+B+D}})+C({\overline {ACD}})$

$S_{3}=({\overline {(A+B).C}})+({\overline {D(C+B)}})$

$S_{4}=({\bar {A}}+{\bar {B}}+{\bar {C}}).(A+B+{\bar {C}})$

$S_{5}={\bar {A}}.{\bar {B}}.C+{\bar {A}}.B.C+{\bar {A}}.B.{\bar {C}}+A.B.C+A.B{\bar {C}}$

$S=({\overline {A+B}})$

$S=A.B\,$

$S=A\oplus B\,$

$S={\bar {A}}\,$

$S=A+B\,$

$S=BC{\bar {D}}+B{\bar {C}}{\bar {D}}+{\bar {B}}C{\bar {D}}+{\bar {B}}{\bar {C}}{\bar {D}}\,$

$S=(C+D).(C+{\bar {D}})$

$S=AB{\bar {C}}D+{\bar {A}}{\bar {B}}C{\bar {D}}+{\bar {A}}{\bar {B}}{\bar {C}}{\bar {D}}+{\bar {A}}{\bar {B}}{\bar {C}}D$

$S=({\overline {({\overline {A.B}})+({\overline {C.D}})}})+A({\overline {A+B}})+B({\overline {C+D}})$

$S=({\overline {A({\overline {B+C}})}}).({\overline {({\bar {A}}+C)+{\bar {B}}}})$

<<	<>	>>

@@ Linha 50: / Linha 50: @@
 <math>S =(\overline{(\overline{A.B})+(\overline{C.D})}) + A(\overline{A+B}) + B(\overline{C+D})</math>
-<math>S =(\overline{A(\overline{B+C})}).( \overline{(\bar A+C).\bar B})</math>
+<math>S =(\overline{A(\overline{B+C})}).( \overline{(\bar A+C)+\bar B})</math>
 =Material de Apoio=